whether overflow occurred. Improve overflow-detection to use
only one conditional branch total, rather than 2N+1
conditional branches for an N-digit number.
/* An implementation with uintmax_t longer than long, but with no
known way to convert it. Do it by hand. Assume base 10. */
uintmax_t n = 0;
- int overflow = 0;
+ uintmax_t overflow = 0;
for (; '0' <= *ptr && *ptr <= '9'; ptr++)
{
uintmax_t n10 = n * 10;
int digit = *ptr - '0';
- overflow |= ! (n10 / 10 == n && n10 < n10 + digit);
+ overflow |= n ^ (n10 + digit) / 10;
n = n10 + digit;
}
if (endptr)